開発環境
- macOS Sierra - Apple (OS)
- Emacs (Text Editor)
- JavaScript (プログラミング言語)
- Node.js, Safari(JavaScript エンジン)
- Learning JavaScript [邦訳](参考書籍)
Think Perl 6: How to Think Like a Computer Scientist (Laurent Rosenfeld(著)、Allen B. Downey(著)、Oreilly & Associates Inc)の Part 1(Starting with the basics)、Chapter 5(Fruitful Subroutines)の Exercises. を JavaScript で取り組んでみる。
Exercises.
コード(Emacs)
HTML5
<pre id="output0"></pre> <button id="run0">run</button> <button id="clear0">clear</button> <script src="sample1.js"></script>
JavaScript
let btn0 = document.querySelector('#run0'), btn1 = document.querySelector('#clear0'), pre0 = document.querySelector('#output0'), p = (x) => pre0.textContent += x + '\n', range = (start, end, step=1) => { let result = []; for (let i = start; i < end; i += step) { result.push(i); } return result; }; let ack = (m, n) => { if (m === 0) { return n + 1; } if (m > 0 && n === 0) { return ack(m - 1, 1); } return ack(m - 1, ack(m, n - 1)); }; let firstL = (word) => word.substring(0, 1), lastL = (word) => word.substring(word.length - 1), middleL = (word) => word.substring(1, word.length - 1); let isPalindrome = (word) => word.length <= 1 ? true : firstL(word) === lastL(word) ? isPalindrome(middleL(word)) : false; let isPowerOf = (a, b) => a === 1 ? true : a % b === 0 && isPowerOf(Math.floor(a / b), b); let gcd = (a, b) => b === 0 ? a : gcd(b, a % b); let output = () => { p('2.'); range(1, 4) .forEach((m) => range(1, 5) .forEach((n) => p(`ack(${m}, ${n}) => ${ack(m, n)}`))); p('3-3'); p(isPalindrome('')); p(isPalindrome('a')); p(!isPalindrome('ab')); p(isPalindrome('aba')); p(!isPalindrome('abc')); p(isPalindrome('abba')); p(!isPalindrome('abca')); p('4.'); range(1, 21) .forEach((a) => range(2, 4) .forEach((b) => { if (isPowerOf(a, b)) { p(`${a} is power of ${b}`); } else { p(`${a} is not power of ${b}`); } })); p('5.'); range(2, 11) .forEach((a) => range(2, 11) .forEach((b) => p(`(${a}, ${b}) = ${gcd(a, b)}`))); }; btn0.onclick = output; btn1.onclick = () => pre0.textContent = ''; output();
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