開発環境
- macOS Sierra - Apple (OS)
- Emacs (Text Editor)
- JavaScript (プログラミング言語)
- Node.js, Safari(JavaScript エンジン)
- Learning JavaScript [邦訳](参考書籍)
Head First Python (Paul Barry (著)、O'Reilly Media)のChapter 3.(Structured Data: Working with Structured Data)、Iterating Over a Dictionary with "items" の FREQUENCY COUNT MAGNETS(No. 2256) を JavaScript で取り組んでみる。
FREQUENCY COUNT MAGNETS(No. 2256)
コード(Emacs)
HTML5
<pre id="output0"></pre> <label for="word0">word: </label> <input id="word0" type="text" value="JavaScript"> <button id="run0">run</button> <button id="clear0">clear</button> <script src="sample1.js"></script>
JavaScript
let pre0 = document.querySelector('#output0'), btn0 = document.querySelector('#run0'), btn1 = document.querySelector('#clear0'), input0 = document.querySelector('#word0'), inputs = [input0], range = (start, end, step=1) => { let res = []; for (let i = start; i < end; i += step) { res.push(i); } return res; }, p = (x) => pre0.textContent += x + '\n'; let vowels = ['a', 'e', 'i', 'o', 'u']; let output = () => { let word = input0.value, found = {}; vowels.forEach((letter) => found[letter] = 0); word.split('').forEach((letter) => { if (vowels.indexOf(letter) !== -1) { found[letter] += 1; } }); p(word); Object.entries(found) .sort(([x, x0], [y, y0]) => x < y ? -1 : x === y ? 0 : 1) .forEach(([k, v]) => p(`${k} was found ${v} time(s).`)); }; let clear = () => pre0.textContent = ''; btn0.onclick = output; btn1.onclick = clear; inputs.forEach((input) => input.onchange = output); output();
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