数学 - Python - JavaScript - 解析学 - 積分 - 積分法 - 上方和および下方和(逆数、関数、区間、分割)

学習環境

Surface 3 (4G LTE)、Surface 3 タイプカバー、Surface ペン(端末)
Windows 10 Pro (OS)
Nebo(Windows アプリ)
iPad Pro + Apple Pencil
MyScript Nebo(iPad アプリ)
参考書籍

解析入門原書第3版 (S.ラング(著)、松坂和夫(翻訳)、片山孝次(翻訳)、岩波書店)の第3部(積分)、第9章(積分法)、5(上方和および下方和)、練習問題2.を取り組んでみる。

1. 上方和。
  
  $\begin{array}{l} \frac{1}{2} (\frac{2}{2} + \frac{2}{3} + \frac{2}{4} + \frac{2}{5}) \\ = \frac{1}{2} \cdot \frac{120 + 80 + 60 + 48}{120} \\ = \frac{60 + 40 + 30 + 24}{120} \\ = \frac{30 + 20 + 15 + 12}{60} \\ = \frac{77}{60} \end{array}$
  
  下方和。
  
  $\begin{array}{l} \frac{1}{2} (\frac{2}{3} + \frac{2}{4} + \frac{2}{5} + \frac{2}{6}) \\ = \frac{120 + 90 + 72 + 60}{360} \\ = \frac{60 + 45 + 36 + 30}{180} \\ = \frac{20 + 15 + 12 + 10}{60} \\ = \frac{57}{60} \end{array}$
2. 上方和。
  
  $\begin{array}{l} \frac{1}{3} (\frac{3}{3} + \frac{3}{4} + \frac{3}{5} + \frac{3}{6} + \frac{3}{7} + \frac{3}{8}) \\ = \frac{1}{3} + \frac{1}{4} + \frac{1}{5} + \frac{1}{6} + \frac{1}{7} + \frac{1}{8} \end{array}$
  
  下方和。
  
  $\begin{array}{l} \frac{1}{3} (\frac{3}{4} + \frac{3}{5} + \frac{3}{6} + \frac{3}{7} + \frac{3}{8} + \frac{3}{9}) \\ = \sum_{n = 4}^{9} \frac{1}{n} \end{array}$
3. 上方和。
  
  $\frac{1}{4} (\frac{4}{4} + \frac{4}{5} + \dots + \frac{4}{11}) = \sum_{n = 4}^{11} \frac{1}{n}$
  
  下方和。
  
  $\sum_{n = 5}^{12} \frac{1}{n}$
4. 上方和。
  
  $\frac{1}{n} (\frac{n}{n} + \frac{n}{n + 1} + \dots + \frac{n}{3 n - 1}) = \sum_{k = n}^{3 n - 1} \frac{1}{k}$
  
  下方和。
  
  $\sum_{k = n + 1}^{3 n} \frac{1}{k}$

コード(Emacs)

Python 3

#!/usr/bin/env python3
from sympy import pprint, symbols, summation

i, n = symbols('i, n', integer=True)
x = symbols('x')
f = 1 / x
u = 1 / n * summation(f.subs({x: 1 + i / n}), (i, 0, 2 * n - 1))
l = 1 / n * summation(f.subs({x: 1 + i / n}), (i, 1, 2 * n))

for n0 in [2, 3, 4]:
    d = {n: n0}
    for g in [u, l]:
        h = g.subs(d)
        for t in [h, h.doit()]:
            pprint(t)
            print()
        print()
    print()

for t in [u, l]:
    pprint(t.factor())
    print()

入出力結果(Terminal, Jupyter(IPython))

$ ./sample2.py
  3        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   2    
 ╱         
╱          
‾‾‾‾‾      
i = 0      
───────────
     2     

77
──
60


  4        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   2    
 ╱         
╱          
‾‾‾‾‾      
i = 1      
───────────
     2     

19
──
20



  5        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   3    
 ╱         
╱          
‾‾‾‾‾      
i = 0      
───────────
     3     

341
───
280


  6        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   3    
 ╱         
╱          
‾‾‾‾‾      
i = 1      
───────────
     3     

2509
────
2520



  7        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   4    
 ╱         
╱          
‾‾‾‾‾      
i = 0      
───────────
     4     

32891
─────
27720


  8        
_____      
╲          
 ╲      1  
  ╲   ─────
   ╲  i    
   ╱  ─ + 1
  ╱   4    
 ╱         
╱          
‾‾‾‾‾      
i = 1      
───────────
     4     

28271
─────
27720



2⋅n - 1      
  ____       
  ╲          
   ╲      1  
    ╲   ─────
    ╱   i + n
   ╱         
  ╱          
  ‾‾‾‾       
 i = 0       

 2⋅n       
 ____      
 ╲         
  ╲     1  
   ╲  ─────
   ╱  i + n
  ╱        
 ╱         
 ‾‾‾‾      
i = 1      

$

HTML5

<div id="graph0"></div>
<pre id="output0"></pre>
<label for="r0">r = </label>
<input id="r0" type="number" min="0" value="0.5">
<label for="dx">dx = </label>
<input id="dx" type="number" min="0" step="0.001" value="0.001">
<br>
<label for="x1">x1 = </label>
<input id="x1" type="number" value="0">
<label for="x2">x2 = </label>
<input id="x2" type="number" value="5">
<br>
<label for="y1">y1 = </label>
<input id="y1" type="number" value="0">
<label for="y2">y2 = </label>
<input id="y2" type="number" value="5">
<br>
<label for="n0">n = </label>
<input id="n0" type="number" min="1" step="1" value="2">

<button id="draw0">draw</button>
<button id="clear0">clear</button>

<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/d3/4.2.6/d3.min.js" integrity="sha256-5idA201uSwHAROtCops7codXJ0vja+6wbBrZdQ6ETQc=" crossorigin="anonymous"></script>

<script src="sample2.js"></script>

JavaScript

let div0 = document.querySelector('#graph0'),
    pre0 = document.querySelector('#output0'),
    width = 600,
    height = 600,
    padding = 50,
    btn0 = document.querySelector('#draw0'),
    btn1 = document.querySelector('#clear0'),
    input_r = document.querySelector('#r0'),
    input_dx = document.querySelector('#dx'),
    input_x1 = document.querySelector('#x1'),
    input_x2 = document.querySelector('#x2'),
    input_y1 = document.querySelector('#y1'),
    input_y2 = document.querySelector('#y2'),
    input_n0 = document.querySelector('#n0'),
    inputs = [input_r, input_dx, input_x1, input_x2, input_y1, input_y2,
             input_n0],
    p = (x) => pre0.textContent += x + '\n',
    range = (start, end, step=1) => {
        let res = [];
        for (let i = start; i < end; i += step) {
            res.push(i);
        }
        return res;
    };

let f = (x) => 1 / x;

let draw = () => {
    pre0.textContent = '';

    let r = parseFloat(input_r.value),
        dx = parseFloat(input_dx.value),
        x1 = parseFloat(input_x1.value),
        x2 = parseFloat(input_x2.value),
        y1 = parseFloat(input_y1.value),
        y2 = parseFloat(input_y2.value),
        n0 = parseInt(input_n0.value, 10);

    if (r === 0 || dx === 0 || x1 > x2 || y1 > y2) {
        return;
    }    

    let points = [],
        lines = [],
        fns = [[f, 'green']],
        fns1 = [],
        fns2 = [];

    for (let i = 1; i <= 3; i += 1 / n0) {
        lines.push([i, y1, i, y2, 'red']);
    }
    fns
        .forEach((o) => {
            let [f, color] = o;
            for (let x = x1; x <= x2; x += dx) {
                let y = f(x);

                points.push([x, y, color]);
            }
        });

    fns1
        .forEach((o) => {
            let [f, color] = o;
            
            lines.push([x1, f(x1), x2, f(x2), color]);
        });
    
    fns2
        .forEach((o) => {
            let [f, color] = o;
            for (let x = x1; x <= x2; x += dx0) {
                let g = f(x);
                lines.push([x1, g(x1), x2, g(x2), color]);
            }
        });
    
    let xscale = d3.scaleLinear()
        .domain([x1, x2])
        .range([padding, width - padding]);
    let yscale = d3.scaleLinear()
        .domain([y1, y2])
        .range([height - padding, padding]);

    let xaxis = d3.axisBottom().scale(xscale);
    let yaxis = d3.axisLeft().scale(yscale);
    div0.innerHTML = '';
    let svg = d3.select('#graph0')
        .append('svg')
        .attr('width', width)
        .attr('height', height);

    svg.selectAll('line')
        .data([[x1, 0, x2, 0], [0, y1, 0, y2]].concat(lines))
        .enter()
        .append('line')
        .attr('x1', (d) => xscale(d[0]))
        .attr('y1', (d) => yscale(d[1]))
        .attr('x2', (d) => xscale(d[2]))
        .attr('y2', (d) => yscale(d[3]))
        .attr('stroke', (d) => d[4] || 'black');

    svg.selectAll('circle')
        .data(points)
        .enter()
        .append('circle')
        .attr('cx', (d) => xscale(d[0]))
        .attr('cy', (d) => yscale(d[1]))
        .attr('r', r)
        .attr('fill', (d) => d[2] || 'green');

    svg.append('g')
        .attr('transform', `translate(0, ${height - padding})`)
        .call(xaxis);

    svg.append('g')
        .attr('transform', `translate(${padding}, 0)`)
        .call(yaxis);

    [fns, fns1, fns2].forEach((fs) => p(fs.join('\n')));
};

inputs.forEach((input) => input.onchange = draw);
btn0.onclick = draw;
btn1.onclick = () => pre0.textContent = '';
draw();

r = dx =
x1 = x2 =
y1 = y2 =
n =

Kamimura's blog

2018年1月15日月曜日

数学 - Python - JavaScript - 解析学 - 積分 - 積分法 - 上方和および下方和(逆数、関数、区間、分割)

0 コメント:

コメントを投稿